How to calculate aspect ratio

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#1

I’m not trying to find the aspect ratio. (It can be found using X/Y). I’m trying to use the aspect ratio to find the Y value. The only inputs I have are the X Value and Aspect Ratio.

function GetAspectRatioValues(X, OriginalSize)
     local Val = X / OriginalSize
     return Val * OriginalSize
end

This worked fine for a while. But then I started adding the ability to resize the UI. And it all messed up. If this is confusing as questions and I will give you the info you need.

#2

From what I understand you’re trying to get the Y size only of the aspect ratio
You should just have to do:

X/Ratio

Right now you’re doing

X/Ratio * Ratio

Which just returns the X value cause the ratio cancels out

#3

No. I was doing

temp: CurrentX (200) / OrigninalX (150)

Y: Temp (1.333) * CurrentY (185)

Y = 246

In the examples on the first post and this one, the ratio was never present. Im trying to bring the ratio in to replace having to save OriginalX

#4

The aspect ratio also depends on which axis the major axis is. For the major axis being X:

YSize = XSize / AspectRatio

If the aspect ratio uses the Y axis as its major axis, then:

YSize = XSize * AspectRatio

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#5

Is originalSize a vector2 value?
Either way it’s still just dividing then multiplying, unless you meant the second line of the function to have a different variable, like originalSizeY for example

#6

I found this out right before you posted it. Thanks anyways!

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#7

If you’re making a function that returns the aspect ratio of a certain 2d rectangle given a Vector2 value, then the function would look like:

function GetAspectRatio(Size)
    return Size.X / Size.Y -- assuming x is the major axis
end

To get a size that fits an aspect ratio given an aspect ratio and a scalar X, you would use a function like this:

function GetAspectSize(XScale, AspectRatio)
    return Vector2.new(X, X / AspectRatio); --returns the x and y sizes respectively, fitting the aspect ratio
end
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