It like this : 98,675 = 98.675 x 10 power by 3
i want to do like calculate this on vector3 like 5143 , 534 , 54355 each number/digit are different
It like this : 98,675 = 98.675 x 10 power by 3
i want to do like calculate this on vector3 like 5143 , 534 , 54355 each number/digit are different
you can just use inverse operations, so first we need to make an expression:
n = a * 10^b
where:
n is the number
a is the coefficient
b is the exponent/power
to find a:
a = n/(10^b)
to find b:
b = floor(log10(n))
so we can derive from those to get the a and b:
local b = math.floor(math.log(n, 10))
local a = n/(10^b)
local notation = `{a} x 10^{b}`
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