Hi. I’ve come up with a scripting idea but I need help with this part. How would I go about finding this angle?
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You can use the
math.atan2(x,y)
function, as it would take in two values, the x difference and the z difference
an application of this would look something like this:
local p1 --position 1
local p2 --position 2
local diff = p1-p2;
local degrees = math.deg(math.atan2(diff.X,diff.Z));
for example, if i wanted angle x. i would do
Addition: I would like to say that this is , for lack of a better word “directional”
math.deg(math.atan2(1,math.sqrt(3))) -> 30 degrees
however, if i wanted angle z, i would flip the two values and do
math.deg(math.atan2(math.sqrt(3),1)) -> 60 degrees
(*it’s implied that the triangle is a right triangle (i forgot to draw the angle marking))
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I have another question if you don’t mind.
This is a little hard for me to explain so I’ll draw a picture.
Let’s say I want to make a point from an angle from the starting point.
In this case let’s make the blue angle 30 degrees, the red line 20 studs, and the purple X is the new point i’m trying to find.
How would I find X?
Well, you can use a bit of trigonometry, as the Pythagorean identity dictates:
polar grid graph:
using that, we can plot a point on a circle with radius r by doing
where theta. the dashed zero, is the angle of that part, and r is the radius of the circle
putting that into roblox, we get:
local angle = math.rad(30)--convert to radians
local origin = origin.Position
local radius = 10 --the distance between the parts
Part.Position = origin + Vector3.new(math.sin(angle)*radius,0,math.cos(angle)*radius)
the reason there isn’t any squaring the the declaration of the Position is because that is to calculate the distance/radius
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