How to get the first value in a dictionary if its name is a number?

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#1

I have a dictionary that looks something like this:

local t = {
	[43957] = "a",
	[42498] = "b",
	[85387] = "c"
}

I was wondering on how I could get the very first value in this dictionary. I can’t do t[1] because the script would think I’d be referring to a value in the dictionary with the name “[1]” (which doesn’t exist) and it would error.

I also can’t do t[43957] because I’m using an API, and that number changes every time.

Thanks in advance.

#2

Here’s the answer:

next time try to do some researching and googling before asking. only ask if you cannot find the answer :slight_smile:

#3

That is not what I meant. In the example you provided, the names of the values in said dictionary are strings, I’m trying to find the first value in a dictionary where all the values are numbers.

And, upon testing with the code anyway, it errored.

#4

No need to be so rude, I was only trying to help. May i ask what was the error?

#5

You may use for key, value in pairs(dictionary) do

and on the first time the loop plays, break the for loop

#6

use

print(next(t))

to get the first item.

1 Like
#7

That’s what I basically told them but apparently they say it does not work.

#8

Oh, my bad, but I don’t see the problem with next? Not sure why he would say it doesn’t work.

1 Like
#9

Use a for loop

for i,v in pairs(Table) do
    if type(i) == "number" then
        -- code here
    end
    break -- use break because we only need index 1
end
3 Likes
#10

Also pretty much what I told him, but he has not responded.

#11

I tried it with a different table and it worked, it’s likely something wrong with the API. Thank you for your help

1 Like