How To Know If A Number Is Odd

[Dede_4242]

I don’t actually have a problem, I’m asking this because I’m courious

[OliveGord]

You can take the modulo of a number, which provides its remainder, if the remainder of % 2 is 0, than your number is even, here is a quick example:
number = 5

if number % 2 != 0:
print(“The number is odd”)
else:
print(“The number is even”)

[Dede_4242]

That doesn’t work, I get either 0.02 (1) or 0.04 (2)

[AmoraFolf (Amora)]

Not to mention the many syntax errors. Looks like it was written in C#

In Lua, it would be like this

local number = 5

if number % 2 ~= 0 then
	print("The number is odd")
else
	print("The number is even")
end

And yes, it does actually work

[Dede_4242]

Strangely this is what I get;

Also the code seemed strange, now I know it’s in C#

[AmoraFolf (Amora)]

@Dede_4242

Strangely this is what I get;

When it runs, however:

[Dede_4242]

I don’t know what I’m doing wrong, also thanks for the solution!
Also, it gives me the result when I type 5%2 in the search bar, but not in the calculator, Google is broken…

[AmoraFolf (Amora)]

Google calculator’s issue is that it multiplies it by two for some reason, no matter what you do. Bing’s calculator and the TI-84 I have in my backpack work normally lol

[hayper1919 (hayper)]

You are calculating 5 percent times 2, which result in 10 percent, or 0.1.

You are suppose to type 5 % 2.

[mhmdsndb3 (Printer)]

I think you mean checking if its a number right?

[SomeFedoraGuy (rusuRares)]

Based on the topic title and description, no.