How to make a function on player removing and [1] in table

Help and Feedback Scripting Support
#1

Hello there,
I am trying to make a function if someone leaves from the game, while being in a table. And if the player is first in the table, then something happens.

I already have a script with a on player removing function, but i don’t know how to make it.

I tried to figure it out by myself, but i was unable to solve the problem.

For example, someone’s in table at position 1, then leaves or disconnect the server. I wan’t some function if the player is at position 1 and leaves the server. How can i make it?

-- Code i've trying to fix
game.Players.PlayerRemoving:Connect(function(plr)
	local player = table.find(queue, plr)
	if player == nil or player == -1 or player == 0 then 
		warn("Player not in table!") -- the player is not in the table
	elseif table.find(queue[1], plr) then -- if player is in queue position 1 and leaves the game
		print("Worked")
	end
end)
1 Like
#2

Why do you need Queue[1]? Is there a table inside a table?

3 Likes
#3

I need the Queue[1], because if the player is in queue position 1, then the player will be removed(i know how to make it), but it also moveto next player in queue

#4

Pretty sure that’s not how it works, please give us the full script for context.

1 Like
#6

and

are two different scripts. Please tell us which is the one that’s not working.

#7 
game.Players.PlayerRemoving:Connect(function(plr)
	local player = table.find(queue, plr)
	if player == nil or player == -1 or player == 0 then 
		warn("Player not in table!") -- the player is not in the table
	elseif table.find(queue[1], plr) then -- if player is in queue position 1 and leaves the game
		print("Worked")
	end
end)
#8 
game.Players.PlayerRemoving:Connect(function(plr)
	local player = table.find(queue, plr)
	if player == nil or player == -1 or player == 0 then 
		warn("Player not in table!") -- the player is not in the table
	else
        
		table.remove(queue, player) -- if player is in queue position 1 and leaves the game
		print("Worked")
	end
end)

Try this.
Wait. I just realised…

#9

If the player leaves but he has to be in [1] queue then something happens.(some function)

#10

This returns an index of the table.

table.find(queue, plr)

so basically

local index = table.find(queue, plr)
if index == 1 then 
	print("Worked...");
else
	warn("Not first in the table!")
end
2 Likes
#11

To check if the player is The First in the Table, you can use :

local count=0
for i, v in pairs(yourtable) do  -- Change 'yourtable' to the table 
   count=count+1
   if v==Plr then
      if count==1 then 
         -- Player is first in table
         -- Do stuff
         break -- Break Loop Because we found What we needed
      end
   end
end
1 Like
#12

There’s no need for that, you can just use table.find…

#13

table.find can be used to check if the player in in the table, but since the player is an instance and not a string im not sure.

(both solutions will work, im sure table.find() will be a much simpler solution but this is the best i got.)

#14

Try this

game.Players.PlayerRemoving:Connect(function(plr)
	local player = table.find(queue, plr)
	if player == nil or player == -1 or player == 0 then 
		warn("Player not in table!") -- the player is not in the table
	elseif queue[1] == plr then -- if player is in queue position 1 and leaves the game
		table.remove(queue, 1)
		print("Worked")
	end
end)
1 Like
#15

if the table is empty, the queue[1] will error.
I suggest adding an if statment to check if the table has values. (if #queue>0 then)

#16

It won’t error, it just won’t output anything.

1 Like
#17

yeah, my bad.
Sorry for the confusion

#19 
local Game = game
local Players = Game:GetService("Players")

local Array = {}

local function OnPlayerAdded(Player)
	table.insert(Array, Player)
end

local function OnPlayerRemoving(Player)
	local Index = table.remove(Array, Player)
	if Index == 1 then
		--Do code.
	end
end

Players.PlayerAdded:Connect(OnPlayerAdded)
Players.PlayerRemoving:Connect(OnPlayerRemoving)