How to return all other running instances of a function within a function

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#1

Say I have a function like

function A()
     wait(10)
     print(1)
end

Now say I called function A. Then I called it again. I want the second call to return all previous instances of the function so that it only prints ‘1’ one time. How would I go about doing this?

#2

What do you mean by “all previous instances of the function”?

#3

All current versions of the function that are still running

#4

I really don’t understand what you are trying to achieve.

#5

An easier solution is to give each function call its own “ID” and if it is outdated, stop execution after the wait.

local i = 0
function A()
    i += 1
    local id = i
    wait(10)
    if id ~= i then --if function A got executed a second time, in which case "i" will have changed
        return
    end
    print(1)
end

To test:

spawn(A)
spawn(A)

will only print 1 once.