How to see if part name is in table

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1

local table = {“hi”,
“icecream”,
“soda”,
“bloxy soda”,
“WOW”,
“Fruitloops”,
“Hey”,
}

local descendants = game.Workspace:GetDescendants()

for index, descendant in pairs(descendants) do

		if descendant.Name == table then
			descendant:Destroy()
			print("Removed A Threat")
		end
		
	end
2

You can simply use table.find(YourTable, string/Instance that you want to find).

1 Like
3

yes but i have the table list of names i want to destroy the part if it has that name

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4

@XXgamerisaliveXx has the right idea for this issue. Here is the code for a better understand of how this is implicated. table.find() will return nil (false) if it doesn’t find a value and it will return a result (true) if it is found.

local table = {
“hi”,
“icecream”,
“soda”,
“bloxy soda”,
“WOW”,
“Fruitloops”,
“Hey”
}

local descendants = game.Workspace:GetDescendants()

for index, descendant in pairs(descendants) do
	if  table.find(table,descendant.Name) then
		descendant:Destroy()
		print("Removed A Threat")
	end
end
6 Likes
6

Actually table.find() returns nil if it doesn’t find…

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7

nil is false when put through a if statement.

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8

but if you try to print print(table.find(table, Name)) and if it finds the value given then it returns its index in the table else nil.

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9

Yes, but as stated on Lua.org…

consider false and nil as false and anything else as true

2 Likes
10

any other values returned as long at it isnt nil or false, is interpreted as true

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11

Yo this exists xd

workspace:FindFirstChild("Name", true) -- the 2nd arg means whether it's cursive or not so it goes thru descendants
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12

That’s for truthy and falsy values and implicit boolean conversions, implying that table.find returns literal false (equals to false) if it doesn’t exist is wrong.

table.find indeed returns nil if the item doesn’t exist. Don’t mix literal false and falsy values up.

2 Likes