How would i check a player chat, for values 1 and 2?

[Ultrahoon]

For this issue, i want to check when the player chats, 1. If the command is used first. and 2. What is the varible they are specifying.

The main problem with this, is when i do this, the output will just print the table ID and won’t go any futher. Also, if i just check if they used the command, it will fail + stop if i say anything else with it. “!Spawn Cheeseburger” (Will fail)

I’ve tried using str:split(" "), but this will still only check for str[1] and will ignore str[2]

P.Chatted:Connect(function(c)
	local SimplifiedChat = c:split(" ")
	print(SimplifiedChat)
. . .
if SimplifiedChat[1] == TCmds["TowerSpawn"] and SimplifiedChat[2] == table.find(TNames, SimplifiedChat[2]) then

[DemonLexe (lex)]

This is your problem right here:

Chatted returns an instance, a message, and a color. You are trying to parse the instance which is why it make a table

If you’re using this Chat | Roblox Creator Documentation

[DemonLexe (lex)]

I think this is what you want to use.
https://create.roblox.com/docs/reference/engine/classes/Players#PlayerChatted

code segment from docs:

local Players = game:GetService("Players")

local function onPlayerChatted(playerChatType, sender, message, recipient)
	print(sender.Name, "-", message, "-", playerChatType, "-", (recipient or "All"))
end

Players.PlayerChatted:Connect(onPlayerChatted)

[hbgnhu (CrimKing)]

Where Did you get this?? Player.Chatted only returns a message and a player object

[madonchik123 (SharkBloxYT)]

im pretty sure its a npc chatted event not player.chatted

[DEVLocalPlayer (LocalPlayer)]

Have you tried debugging? Use ipairs, loop through the table of strings and see what’s wrong. Maybe it’s not :split that doesn’t work, but the checks you do in the next lines.

[hbgnhu (CrimKing)]

I mean it says

@Ultrahoon

For this issue, i want to check when the player chats

So I doubt they are talking about an NPC

[madonchik123 (SharkBloxYT)]

player.Chatted only returns message and receipt

[majdTRM]

Correct me if I’m wrong but

and SimplifiedChat[2] == table.find(TNames, SimplifiedChat[2])

Should just be

table.find(TNames, SimplifiedChat[2])

[BendsSpace]

Player.Chatted has the parameters message recipient. Chat.Chatted has the parameters part, message, color.

The OP is using Player.Chatted, so their code is correct in that regard.

Split always returns a table of strings. For example:

local splitString = "a b c":split(" ")
-- splitString is now {"a", "b", "c"}

I would print out the split parts of the string to make sure they’re what you want.

This expression also doesn’t make sense:

SimplifiedChat[2] == table.find(TNames, SimplifiedChat[2])

For this to be true, there would have to be a table key that is equal to SimplifiedChat[2] and the same as the key.

For example, if SimplifiedChat[2] was “xyz” this would only return true if the table TNames contained: {xyz = “xyz”}, which doesn’t make sense.

You may be trying to check if the table contains the value, in which case you should use only table.find(TNames, SimplifiedChat[2]).

[hbgnhu (CrimKing)]

How would i check a player chat, for values 1 and 2?

Player.Chatted has the parameters message recipient. Chat.Chatted has the parameters part, message, color. The OP is using Player.Chatted, so their code is correct in that regard. Split always returns a table of strings. For example: local splitString = "a b c":split(" ") -- splitString is now {"a", "b", "c"} I would print out the split parts of the string to make sure they’re what you want. This expression also doesn’t make sense: SimplifiedChat[2] == table.find(TNames, SimplifiedChat[2])…

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(30 letters)