Is there a way to smooth numbers?

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#1

hi , is there a way to polish values? because my calculator script make things like 283.873867836386387, is there a way to make it so its just 283?

#3

so i do thing.Value = something / 2.38 and then math.floor(thing.Value)?

#5

so this would be right? : S4P.Value = math.floor(S4P.Value)

#7

but what does math.floor normally does?

#8

Math.floor returns the largest smaller integer you call it with. For more information about the math library, read here: lua-users wiki: Math Library Tutorial

#9

yeah thats what i need, doing math.floor on 1.2927 would do 0 or 2

#10

Oh sorry, I think I misread your original question. Call math.floor without adding 0.5 and you should be good.

Calling math.floor on 1.2927 will return 1.

#11

If you read over the math page on the developers hub there are a few math methods you can use to do this: math | Documentation - Roblox Creator Hub.

math.ceil:
In short this will always round the number up. Here is a little example:

local Number = math.ceil(1.2344)
print(Number)
-- prints 2

math.floor:
In short this will always round the number down. Here is a little example:

local Number = math.floor(1.62344)
print(Number)
-- prints 1
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#12

There’s also math.modf which will literally separate the integral and the fractional part of a number. You can use this and discard the fractional if you’re uninterested in rounding.

local number = 283.873867836386387
local integral = math.modf(number)
print(integral) -- 283

*edit: This is functionally identical to math.floor so you should just use that, actually.

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#13

Alternatively if you want to round like they taught in grade school you’d do something like

local RoundedNumber = math.floor(Num + .5);
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#14

For this use case, this functions identically to math.floor, as floor rounds down no matter what, getting rid of the decimal and leaving the integer.

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#16

Best way of achieving polish values is this.

local number = 0.4

print(math.floor(number + 0.5)) -- 0

local number = 0.5

print(math.floor(number + 0.5)) -- 1

local number = 1.1

print(math.floor(number + 0.5)) -- 1

local number = 1.6

print(math.floor(number + 0.5)) -- 2
1 Like