Is there any other way for me to shorten this code?

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1

How could I shorten lines 7 and 8’s y values?

while true do
	task.wait(5)
	
	local rightCF2 = RootPartCF * CFrame.new(math.random(1, 5), math.random(-1, 4), -3.5)
	local leftCF2 = RootPartCF * CFrame.new(math.random(-5, -1), math.random(-1, 4), -3.5)
	
	local rightCF1 = RootPartCF * CFrame.new(math.random(2, 4), rightCF2:ToObjectSpace(RootPartCF):Inverse().Y - 1.5, math.random(1, 3))
	local leftCF1 = RootPartCF * CFrame.new(math.random(-4, -2), leftCF2:ToObjectSpace(RootPartCF):Inverse().Y - 1.5, math.random(1, 3))
	
	local CF3 = 'place holder value'
end

I am trying to make it so rightCF1’s Y value will always be 1.5 less than rightCF2’s Y value. This works however I wonder if there is another way that gets me the exact same results but uses less coding and is better suited for cases like these. What I did was I found the offset of rightCF2’s from the RootPartCF and subtracted 1.5 from that offsets Y value. (Same thing for leftCF1)

2

It looks just fine, it just ends up being alot tankier than lines 4&5
If you want you can move the content after the comma down on the line below to make it easier to read

4

It already looks good. You should just move the lines apart to make them easier to read. (Also in my experience you should use Random.new():NextInteger(n1, n2) instead of math.random(n1, n2) since it generates more random numbers for me)