Looping String.Split() Not Working

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#1

Hello! I am attempting to make a function that loops through string.split(), but it does not look like the loop is picking up the result.
:rocket: What do I want to achieve?
I am attempting to make a function that converts a string with commas into an array. Here is an example:
"Test 1,Test 2,Test 3" :arrow_right: {"Test 1", "Test 2", "Test 3"}
:x: What is the issue?
The output of the function is always: image
:white_check_mark: What solutions have I tried so far?
I have tried to look up solutions on the DevForum, but there are no answers that help!

:page_with_curl: The Code
image Script

function CommaStringToArray(InputString)
	print(InputString) -- This will print the InputString parameter correctly!
	local ArrayResult = {}
	for CurrentIndex, CurrentString in pairs(string.split(InputString, ",")) do
		print(CurrentString[CurrentIndex]) --> nil
		table.insert(ArrayResult, CurrentString[CurrentIndex])
	end
	return ArrayResult
end
print(CommaStringToArray("Test1,Test2,Test3")) --> nil
print(CommaStringToArray("Test")) --> nil

What is the issue here? Am I missing something?

Thanks,
image TriumphantCreatorX

#2

I’m confused as to why you wouldn’t run it like this?

function CommaStringToArray(InputString)
	return string.split(InputString, ",")
end
print(CommaStringToArray("Test1,Test2,Test3")) --> nil
print(CommaStringToArray("Test")) --> nilprint("Hello world!")

String.split returns an array anyway?

2 Likes
#3

Hello, @AstraI_YT!
This was because I was most likely going to add more to the function. I am curious as to why looping string.split() does not function and returns nil values. I will mark your reply as the solution because it works as intended, thank you! It looks like looping string.split() is not possible.

#4

You were using for i,v in pairs not ipairs, the index is nil if you use pairs as they are an array, not a dictionary.

IF you used for i,v in ipairs it would work.

Best practice to always use ipairs if it isn’t a dictionary.

2 Likes
#5

The index isn’t ‘nil’ if you use the ‘pairs’ iterator factory function but the order in which the iterable (table) is traversed over in is undefined.