Hi, I feel like im doing something wrong here, im trying to round a number with `math.round`

, but it isnt working, am i doing something wrong, or am i being an idiot? (i feel like i am)

```
print(math.round(100*10)/10) -- just prints 100
```

Hi, I feel like im doing something wrong here, im trying to round a number with `math.round`

, but it isnt working, am i doing something wrong, or am i being an idiot? (i feel like i am)

```
print(math.round(100*10)/10) -- just prints 100
```

1 Like

Uh, what number should it be?, it must round to one decimal place

```
print(math.round(1.85*10)/10) --> 1.9
print(math.round(1.8274285*10)/10) --> 1.8
```

1 Like

Did you accidentally flip the operators? I think this is just confusion.

1 Like

So what im trying to do turn 100 into 1.0 (or simply 1), but if i have 130, i would want it to be 1.3, but for some reason doing this continues to print 100, i think i can use `string.format`

for this, i dont remember

Just divide by 100?

```
print(100/100) --> 1
print(130/100) --> 1.3
```

if it must always have a decimal place

```
print(("%0.1f"):format(130/100)) --> 1.3
print(("%0.1f"):format(100/100)) --> 1.0
```

2 Likes

yeah I just tried that and was about to post it

100*10 is 1,000. Divide 1,000 by 10 and you get 100 as a whole number, so everything seems to be working correctly. Not sure what you want to happen here since you never defined a problem.

math.round will return a whole number that has been either rounded up (if the decimal is 0.5 or greater), or been rounded down (decimal is less than 0.5).

Since the equation you gave above returns a whole number without the need for rounding, there is really no need for math.round().

it’s easy math, you doing (100*10)/10 soo it’s like 1000 /10, and it’s 100

Math.round rounds fractions, like 0.5 and above to 1 and lower to 0

Yeah, then its just a case of me having idiot, thanks

I think you mean Decimals / Floats

1 Like

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