How can I make the elements of the Table swap positions?
--[[
ItemMoveUp("world"):
In -> {
"Hello",
"world",
"Nice"
}
Out -> {
"world",
"Hello",
"Nice"
}
ItemMoveDown("Hello"):
In -> {
"Hello",
"world",
"Nice"
}
Out -> {
"world",
"Hello",
"Nice"
}
]]--
How can I achieve this?
I’ve created a simple function to help with your problem.:
The “newPosition” argument is where the element’s new position would be in the table relative to it’s current position in the table
local function ItemMove(Table:{}, Item:any, newPosition:number)
local Index
Index = table.find(Table, Item)
if not Index then return end
local Value = Table[Index]
local newIndex = math.max(Index+newPosition, 1)
table.remove(Table, Index)
table.insert(Table, newIndex, Value)
end
Testing the function:
Edit: @wsyong11 I used table.find to get the element’s current index whichone assume to be more efficient than my implementation since it was implement by Roblox
Thank you very much!
30 worldsssssss
You’re welcome
local function reverseTable(t : {}) : ({}) -> ({})
local r : {} = table.create(#t)
for i : number = #t, 1, -1 do
table.insert(r, t[i])
end
return r
end
That seems like a useful function on it’s own but if you read the post carefully, they’re trying to move an element in the table to a new position relative to where the element’s current position is
local function moveTable(t : {}, i : number, j : number) : ({}, number, number) -> ()
local v : any = table.remove(t, i)
table.insert(t, j, v)
end
local t = {"a", "b", "c"}
moveTable(t, 1, 3)
print(t[3]) --a
That works too but they’re trying to just call the function which the element. However, your reply has prompted me to use table.find instead in my code so I will make changes to my original solution