Problem With Module Scripts

Help and Feedback Scripting Support
#1

Hey. I have a really small problem that is affecting me a lot. Right now, I have this code in a module

local pets = {
	["Dog"] = Vector2.new(1,270),
	["Cat"] = Vector2.new(271,540),
	["Turtle"] = Vector2.new(541,740),
	["Bunny"] = Vector2.new(741,900),
	["Ferret"] = Vector2.new(901,1000),
}

return pets

Whenever I require it it gives me this order (Or something like it I dont remember perfectly) - Turtle, Cat, Dog, Ferret, Bunny. The problem is, I want it to give it to me in written order.

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#2

Correction. It actually prints out like this image

#3

You’d have to change the indexes to numbers or some sort of ordered character because dictionaries are not ordered naturally I don’t think
(may not be true though)

#4

You may be right because I noticed it’s in alphabetical order

#5

Dictionaries aren’t ordered, you will need to index by number or convert it to an array and then sort it. Why do you need it to be in a specific order? There may be another way to solve this problem if the context was made clear.

#6

Maybe OP can do something like

local animals = {
[1] = {"Cat"},
[2] = {"Dog"}
}

if you need multiple animals in one index

#7

I am calling it from a Gui then turning it into a list from most common to rare. It would look ugly if it was out of order. I need to use the name from the dictionary to get the model from replicated storage so I can use it in a viewport.

I think the solution would be to format it as [“1 Dog”] , [“2 Cat”] and use string manipulation.

#8

The Vector2 is very important so this won’t work. I think I may have found a solution

#9

Why can’t you keep the order of the GUI separate from this list? Simply keep the order of the rarity and refer to that.

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#10

This has the added benefit of allowing you to keep this information separate from the rarity(so that you can change that at will) without having to muck up this table

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#11

Sorry I made a mistake, correction:

local animals = {
    [1] = {
                ["Dog"] = Vector2.new()
            },
}
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