Problem with sorting an array

[Dan_E56 (Dan)]

Code

for index,contestant in pairs(contestants) do
	local total = 0
	local plrs = 0
	for i,v in pairs(globalData) do
		if not excluded[tostring(v["ID"])] then
			local individualRating = v["Ratings"][index]
			if individualRating then
				total = total+individualRating
				plrs+=1
			end
		end
	end
	local average = total/plrs
	ratings[contestant["Name"]] = {
		["Score"] = average,
		["ID"] = contestant["UserId"]
	}
end
table.sort(ratings, function(a,b) return a.Score > b.Score end)
print(ratings)

Here’s the array it prints:

I want it to sort the table based on the scores. High to low.

[WingItMan]

This is likely the solution you need.

Table.sort doesn't sort the table

table.sort can only be used to sort arrays, not dictionaries, what you could do is convert the table into a table of dictionaries (an array) and then perform the sort, as in the following: local mapCounts = { {"map1", 2}, {"map2", 4}, {"map3", 1} } function sortTable(a, b) return a[2] < b[2] end table.sort(mapCounts, sortTable) for i, v in pairs(mapCounts) do print(v[1], v[2]) end This will produce the desired outcome.

Modify your data returned to include the user’s name with the ID and Score…

Test Code

local ratings = {
	{
		["ID"] = "10000",
		["Username"] = "LordDragoniteEz",
		["Score"] = 40
	},
	{
		["ID"] = "10001",
		["Username"] = "NotYoSurf",
		["Score"] = 77
	},
	{
		["ID"] = "10002",
		["Username"] = "ThenewJecan457",
		["Score"] = 53
	}
}

table.sort(ratings, function(a,b)
	print("ATTEMPTING TO SORT",a.Score,b.Score)
	return a.Score > b.Score
end)
print(ratings)