Randomly pick 1 or 100

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#1

i trying to pick 1 or 100 but I don’t know-how.

1 Like
#2 
local randomnumber = math.random(1,100)

print(randomnumber)
#3

This picks a number between 1 and 100 not 1 or 100

#4

you can do

local num = math.random(1, 2) == 1 and 100 or 1

print(num) -- will either be 1 or 100

If the randomnumber is 1, it’ll be 100. If the number is 2 it’ll variable will be 1.

#5

never mind, i tryed putting the print in a loop without the variable in it too

#6

it’ll print 100.

It’s just luck really. The script works fine.

image

also to be sure u can do



for i = 1, 150, 1 do
	local num = math.random(1, 2) == 1 and 100 or 1
	print(num) -- will either be 1 or 100	
end

as u can see it’ll print 100

1 Like
#7

100^(random:NextInteger(0,1))

100^0 = 1

100^1 = 100

1 Like
#8

A rather interesting way would be:

local num = math.clamp(((1000 * math.random(-2,1))+1),1,100)
#9

Another interesting way would be:

local num = table.pack(1,100)[math.random(1,2)]

You can also do it this way I found using linear regression y=ax+b

local num = 99*(math.random(1,2))-98
1 Like
#10 
local result = math.random(1,2)
local number
if result == 1 then
   number = 1
else
   number = 100
end
#11 
local result = 1 + math.random(0,1)*99
print(result)

To test if it is random:

local One = 0
local Hundred = 0
for i = 1, 1000 do
    local result = 1 + math.random(0,1)*99
    if result == 1 then
        One+=1
    else
        Hundred+=1
     end
end
print("1 occured: "..One.." time!")
print("100 occured: "..Hundred.." time!")
#12

Maybe this?

local num = math.random(1,2)

if num == 2 then
	print("1")
else
	print("100")
end
2 Likes
#13

In this instance, you should use elseif num == 1 just incase we want to do this:

local num = math.random(1,100)

if num == 1 then

   print("1")

elseif num == 100 then

    print("100")

end

sorry for bumping btw

1 Like