Rebirths math problem

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#5

That’s a little confusing.
So first rebirth is 10,000
2nd is 30,000
3rd is 30,000 + 20,000?
4th is 50,000 + 30,000?
5th is 80,000 + 50,000?

#6

Actually, yea, its confusing. Here’s correct one:
1 - yourActualRebirths x 10k
2 - yourActualRebirths x 10k
Etc.

But since you rebirthed 1 time, yourActualRebirths would be + 1 so the 2nd rebirth would cost more.

#7

My wording here is fairly confusing so I solved it for you. All you have to do is plug in the values to the script in my post above. start and increment would both be 10000. a and b defined below.

a1 = 10000
d = 10000
s(n) = n / 2 [2a1 + (n - 1) d]
s(n) = n / 2 [20000 + (n - 1) 10000]

s(n) = n / 2 [20000 + 10000n - 10000]
= 10000n + 5000n^2 - 5000n	Divide all by two and multiply by n (n^2 in the case already multiplied by n)
= 5000n^2 + 5000n

Apply quadratic equation.

5000n^2 + 5000n - s(n) = 0
^^^^      ^^^^
a         b
#8

Let me re-explain. Okay, so, you have 1 rebirth. Each rebirth costs your actual rebirth * 10k in this case. So, if you had 2 rebirths, it would cost 20k, 3 rebirths-30k etc.

Now, what I want is to make massive rebirths directly, since rebirthing makes you lose everything you have. So like, I want into the process of finding price, if player chose to rebrith 5 times, it’ll count like that :

local RebirthsIHave = 1

local HowManyRebirths = 5
local price = 0

for i = 1, HowManyRebirths do
    price = price + RebirthsIHave * 10000 -- The price will increase as we rebirth
    RebirthsIHave = RebirthsIHave + 1
end

This would work but I don’t want to use a for loop, I want to get it done instantly, calculating the price only 1 time, meaning it will also calculate the price of the next rebirth until 5 in this case.

#9

For one to the next
cost = (currentRebirths+1)*10,000]

Cost series

1 => 10k
2 => 20k
…
50 = 500k
51 = 510k

For multiple
cR = currentRebirth
nR = numberOfRebirths
cost = (cR*nR + nR(nR+1)/2)*10000
or = nR/2 * (2*cR + nR +1) *10000

complements of @Astr0Derp 10000/2
cost = 5000*nR*(2cR + nR + 1)

can’t make it much prettier
this is say, you have 6
and want to buy 5 (7,8,9,10,11)
the cost is 450,000

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#10

Sorry for all the edits… I didn’t understand what you were trying to do with the RebirthsIHave at first.
The formula is basically this. Will see about simplifying it.

local scale = 10000
local final_price = HowManyRebirths * (HowManyRebirths+1) * scale/2 + scale * ((RebirthsIHave-1)*(HowManyRebirths-1)+ RebirthsIHave-1)

Edit: Here it is simplified

scale = 10000
final_cost = 0.5*scale * HowManyRebirths * (HowManyRebirths + 2*RebirthsIHave - 1)
#11

So pretty much
First Rebirth is 10,000 = 10,000
Second Rebirth is 20,000 + First Rebirth = 30,000
Third Rebirth is 30,000 + second rebirth = 60,000
then 100,000
etc

This is really simple :stuck_out_tongue:

local rebirthsToDo = 20
local startCost = 10000
local rebirthCost = 10000

for i=1, rebirthsToDo do
   rebirthCost = rebirthCost + startCost*i
end
#12

What I would do is make an algorithm for the price to go up. I don’t see a reason for you to use a for loop, just make an algorithm that handles it.

Demonstration:

local PRICE_INCREASE_PER_REBIRTH = player.leaderstats.Rebirths.Value + 1000 / ( player.leaderstats.Rebirths.Value * 5)

This add’s the player’s rebirth value by a thousand and then divides it by the amount of rebirths the player multiplied by 6. ( It doesn’t increase the rebirths, just an algorithm )

#13

Yes, that’s simple but what if player wants to do over a million rebirths? The script would crash.

#14

A million rebirths at once?!?!

#15

Yea, like tapping simulator? That’s why I dont want to use a for loop.

#16

Well I highly doubt that anyone would do that many rebirths at once, however under that case, you could use that script to log the price of each rebirth
Create a table,
Put something like this into the loop

table.insert(rebirthCostTable, rebirthCost)

Then you could call it, otherwise I would look into the algorithms that others have posted here :stuck_out_tongue:

#17

Why are you guys making it this complicated, just use a exponential scale. Any equation of the form y=n^x will work fine, where n is the steepness of the function and x would be the amount of rebirths which you can track by your own means. Using a for loop for any sort of math that isn’t integration(but even integration in most cases) is a massive sign you’re doing something terribly wrong.

#18

he wants the total price of multiple iterations of buying a rebirth not just the price of a specific rebirth

#19

Yes, exactly, I want to be able to calculate the next price and add it to the current one.

#20

Then just integrate whatever formula (exponential formula in this case) for calculating the price and do the exact same thing.

#21

My question is what is the formula?

#22

This is exactly what arithmetic series sums do as I have said above. To get the price of x amount of rebirths it would be s(currentRebirths + x) - s(currentRebirths) where s is the sum function. Refer to my post above for code.

#23

I edited post above, but here it is again:

scale = 10000
final_cost = 0.5*scale * HowManyRebirths * (HowManyRebirths + 2*RebirthsIHave - 1)
#24

Wow, thank you! This is what I was looking for! I printed it and it printed out the exact number I wanted.

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