Rebirths math problem

Help and Feedback Scripting Support
#12

What I would do is make an algorithm for the price to go up. I don’t see a reason for you to use a for loop, just make an algorithm that handles it.

Demonstration:

local PRICE_INCREASE_PER_REBIRTH = player.leaderstats.Rebirths.Value + 1000 / ( player.leaderstats.Rebirths.Value * 5)

This add’s the player’s rebirth value by a thousand and then divides it by the amount of rebirths the player multiplied by 6. ( It doesn’t increase the rebirths, just an algorithm )

#13

Yes, that’s simple but what if player wants to do over a million rebirths? The script would crash.

#14

A million rebirths at once?!?!

#15

Yea, like tapping simulator? That’s why I dont want to use a for loop.

#16

Well I highly doubt that anyone would do that many rebirths at once, however under that case, you could use that script to log the price of each rebirth
Create a table,
Put something like this into the loop

table.insert(rebirthCostTable, rebirthCost)

Then you could call it, otherwise I would look into the algorithms that others have posted here :stuck_out_tongue:

#17

Why are you guys making it this complicated, just use a exponential scale. Any equation of the form y=n^x will work fine, where n is the steepness of the function and x would be the amount of rebirths which you can track by your own means. Using a for loop for any sort of math that isn’t integration(but even integration in most cases) is a massive sign you’re doing something terribly wrong.

#18

he wants the total price of multiple iterations of buying a rebirth not just the price of a specific rebirth

#19

Yes, exactly, I want to be able to calculate the next price and add it to the current one.

#20

Then just integrate whatever formula (exponential formula in this case) for calculating the price and do the exact same thing.

#21

My question is what is the formula?

#22

This is exactly what arithmetic series sums do as I have said above. To get the price of x amount of rebirths it would be s(currentRebirths + x) - s(currentRebirths) where s is the sum function. Refer to my post above for code.

#23

I edited post above, but here it is again:

scale = 10000
final_cost = 0.5*scale * HowManyRebirths * (HowManyRebirths + 2*RebirthsIHave - 1)
#24

Wow, thank you! This is what I was looking for! I printed it and it printed out the exact number I wanted.

1 Like
#25

that will give you your first rebirth free
just so you know

1 Like
#26

Yea, I’ll try to find something for this by myself. Thanks for this notice!

#27

check my first response, it is a very similar formula but it shifts everything 1 spot so starting at 0, it is 10k

#28 
local e = 10 -- steepness of the scale

function expoScale(x)
  return e^x
end

function expoScaleInt(x)
  return (e^(x+1)-1)/(e-1)
end

is what you want

#29

But I don’t understand it, could you repost it more clearly now?

#30

Yours work perfectly but doesn’t include how many rebirths you have rn.

#31

expoScale gives you a curve exponentially increasing by e, expoScaleInt is the analytic form for the series sum of that function.