Remove and read Dictionary

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#1 
local SelectedSpawnPoint = {}

SelectedSpawnPoint["Spawn1"] = "Player1, Player3"

SelectedSpawnPoint["Spawn2"] = "Player2, Player4"

As a example how could i remove Player4 and how could i check how many Players are inside Spawn1 and Spawn2?

Something like:

for index, value in pairs(SelectedSpawnPoint) do

if value == player then

value = nil

end

end

or something like:

print(#SelectedSpawnPoint["Spawn1"])

#2 
local SelectedSpawnPoint = {}

SelectedSpawnPoint["Spawn1"] = "Player1, Player3"
SelectedSpawnPoint["Spawn2"] = "Player2, Player4"

local function RemovePlayerFromSpawns(name: string) 
	-- note we use the *name* of the player, case sensitive
	for stringed, value in pairs(SelectedSpawnPoint) do
		local index = string.find(value, name)
		if index ~= nil then
			local newString = ""
			local endOfName = string.find(value, ", ", index)
			-- we must keep the space!!
			if index ~= 1 then -- we're deleting not the first name
				if endOfName ~= nil then -- we're deleting a name in the middle
					local beforeString = string.sub(value, 1, index - 1)
					local endString = string.sub(value, endOfName + 2, -1)
					newString = beforeString .. endString
					if string.sub(newString, -2) == ", " then
						newString = string.sub(newString, 1, -2)
					end
				else -- we must be trying to delete the last name
					newString = string.sub(value, 1, index - 2)
				end
			else -- we're deleting the first name
				if endIndex ~= nil then
					newString = string.sub(value, endIndex + 2)
				else -- we're deleting the first (and only) name
					newString = ""
				end
			end
			SelectedSpawnPoint[stringed] = newString
			break -- we found the user and removed it, no point in still looping
		end
	end
end

local function CountPlayers(spawnName: string?)
	-- the ": string?" part in the function means the argument "spawnName" can either be a string or nil (aka an optional argument)
	if spawnName ~= nil and SelectedSpawnPoint[spawnName] ~= nil then
		return #string.split(SelectedSpawnPoint[spawnName], ", ") -- we must include the space!
	elseif spawnName == nil then
		local count = 0
		for _, value in pairs(SelectedSpawnPoint) do
			count = count + #string.split(value, ", ")
		end
		return count
	else
		warn "Spawn point is not valid!"
	end
end

or just use arrays like @MakerDoe pointed out below. I was just giving you an option to use strings since you had them originally.

1 Like
#3

This is unnecessary; just use an array instead of strings:

SelectedSpawnPoint["Spawn1"] = { "Player1", "Player3" }

print(#SelectedSpawnPoint["Spawn1"])

table.remove(SelectedSpawnPoint["Spawn1"], table.find(SelectedSpawnPoint["Spawn1"], "Player1"))
2 Likes
#4

It removes all Players in the Table, how could i remove just one?

#5

It prints 1 with print(#SelectedSpawnPoint["Spawn1"]) if there is 2 Players inside, is 0 == 1 for Lua?

#6

What do you mean? If you pass the correct name (for example, call RemovePlayerFromSpawns("Player4")) then it’ll remove that and only that. If you call RemovePlayerFromSpawns("Player") then it’ll break.

#7

endIndex has a yellow line under, is that right?

#8

Oops! Change all instances where it says “endIndex” to “endOfName”. I totally forgot I called it “endOfName” haha

#9

Thanks, it worked, just because im curious does this work with a shorter script like with table.remove() or table.find()?

#10

Not if you’re planning to use strings.

#11

Okay and would that also work if i would insert the player into the Table?

#12

To insert a player you could use this function:

local function InsertPlayerIntoSpawn(spawnName: string, playerName: string)
	SelectedSpawnPoint[spawnName] = SelectedSpawnPoint[spawnName] .. ", " .. playerName
end
1 Like
#13

Okay thanks

1 Like
#14

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