Removing all Text in a string after a underscore

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#1

Let’s say I have this string "Cabin_5123456" and I want to remove the underscore and everything after it so it turns into "Cabin"

my best guess is to search for the _ with string.match then use string.sub to remove the text but I’m not quite sure how to put that into code

I searched for a while and found posts with similar situations but I don’t quite understand how to do it the way I need it to be done

any help is appreciated

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#2

You can look at string pattern captures in the page for string patterns.

A proposed solution would be text:match('^(.-)_'); breaking this down, we know with ^ we match from the start of the string, () means we have a capture which will be returned as a separate variable, and .- will match the least amount of any character it can until it reaches the _ after it. Note that since the _ is not included in the capture, it won’t be returned or anything after it.

You could use it as such.

local cabin_text = my_text:match('^(.-)_')
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#3

I’d use string.find, but it’s the same thing you mentioned. If you use string.find(“_”), you can find the index of where the _ is, then take string.sub(string, 1, index-1) to get everything before it.

Only thing is it won’t support names with _ inside them (eg. Cabin_One_5123456). In that case, you’d need to use string patterns like @AMD_chan mentioned.

#4

string.find is exactly what I needed to make it work, I skipped over it and thought I should use match

#5

I’d like to note there’s also a new string.split API which can be used for this:

string.split("Cabin_1234", "_") --> { "Cabin", "1234" }
string.split("Cozy_Cabin_1234", "_") --> { "Cozy", "Cabin", "1234" }

string.split("Cabin_1234", "_")[1] --> "Cabin"
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#6

Hello! I have been using this, it helped me out a lot. I was wondering how I could do this for all the words after a space instead?

print(string.split(“/warn User Stop spamming chat please”, " ")[2])

How could I make it print “Stop spamming chat please”? Thanks. Hope to hear back soon!

#7

If you want to stick with using string.split you can concatenate all the strings after the second one.

local split_result = string.split("/warn User Stop spamming chat please", " ")
-- concatenate strings after the second one in the list with space
print(table.concat(split_result, " ", 3))
1 Like