Removing Multiple Indexes from a Table

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#1

Afternoon!

Lets say I have the array: array = {true, false, 10, "Hi", 69, true, true}

I want to remove certain entries from this array using table.remove to prevent blank space. These indicies can also be stored in a table. toRemove = {2, 3, 5}

My goal at this point is to iterate through each value in toRemove and remove it from array. For example, the 2 in the toRemove table would remove the false in the array table. However, as stated I want to use table.remove to prevent empty spaces of nil, as these would grow in size very quick and I iterate through this table often in my game code.

I currently have something that works, but seems somewhat unorthadox. Here is what I have and a short description of what it does:

local array = {true, false, 10, "Hi", 69, true, true}
local toRemove = {1,3,4,6}

local function removeIndecies(arrayToRemoveFrom,indeciesToRemove)
    local indeciesToRemove = table.sort(indeciesToRemove) --make sure indecies are in numerical order(this is needed for the method I use below

    --Remove indecies from array.
    for i,indexToRemove in pairs(indeciesToRemove) do
        local indiciesAlreadyRemoved = i-1 --This will equate to how many indicies we have already removed.
        table.remove(arratToRemoveFrom,indexToRemove-indiciesAlreadyRemoved) --We need to subtract how many indicies have already been removed here because table.remove, bumps everything after what was removed, back by one index.
    end

    return arrayToRemoveFrom
end

local newArray = removeIndecies(array,toRemove)

So this method works by recognizing we need to remove, say, index 3 and 4, and then calling table.remove(table,3) twice because that 4th index gets bumped back to 3 after table.remove is called once.

I was basically wondering if there was a quicker or easier way to achieve this behavior?

#2 
function RemoveIndexes(Table, Indexes)
    local NewTable = {}

    for Index, Value in pairs(Table) do
        if not table.find(Indexes, Index) then
            NewTable[Index] = Value
        end
    end

    return NewTable
end

local OldTable = {true, false, 10, "Hi", 69, true, true}
local Indexes = {1, 3, 4, 6}

local NewTable = RemoveIndexes(OldTable, Indexes)

print(OldTable, NewTable, Indexes)

this is how I would personally do it

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