Roblox studio glitch 2023 unsolvable

[concat_nate]

You can write your topic however you want, but you need to answer these questions:
1.I am trying to remove all numbers under 5

2. The problem is it only removes 1 and 3

3. I have tried literally everything

I have ran into this issue with a more complex ipairs loop, i am using this as a debugging/testing sample of code.

local t = {1, 2, 3, 4, 5, 5, 5, 6}; 
for i, v in ipairs(t) do 
   if v < 5 then 
       table.remove(t, i); 
   end; 
end;
print(t);

output:
2
4
5
5
5
6
Please help, i know that

local t = {1, 2, 3, 4, 5, 5, 5, 6};
for i, v in ipairs(t) do 
   if v < 5 then 
      print(t[i]) 
      table.remove(t, i); 
      print(t[i]); 
      continue; 
   end; 
   print(v) 
end 
print(t)

^ that works, but i don’t want to do t[i] = nil or it will lag, please help!

[azqjanna]

Not allowed to change the table while you are iterating over it!

When you do table.remove the rest of the table shifts down, so what happens is:
1 gets removed
2 gets skipped because it is now where 1 was, but the current index is the second number, which is now 3.
Same thing happens again, 3 gets removed, 4 gets skipped.

[concat_nate]

how to fix though i know thats the iussue

[azqjanna]

You could do this:

local s = 0 --How many items have been removed

for i = 1, #t do
	if t[i - s] < 5 then
		table.remove(t, i - s) --Minus s accounts for table shifting down
		s = s + 1
	end
end

edit: fix buge

[concat_nate]

that didn’t work for some reason, i thought it would

[azqjanna]

I just tested it and it works. Did you see I changed t[i - s]?

[ArpeaxVinheim (Arpeax)]

t = {1, 2, 3, 4, 5, 5, 5, 6}; 
for i, v in ipairs(t) do 
   if v < 5 then 
       rawset(t, i, nil); 
   end; 
end; 
t[0] = nil --refreshed after a meta bypass 😎
print(t);

[azqjanna]

Don’t do this because if you remove an element in the middle of the list it will go from acting like a list to acting like a dictionary, the # operator wont work, iterators will handle it different, etc.

[concat_nate]

it’s giving an error, and yes i did see your change

[azqjanna]

What error is it giving now? 12345

[concat_nate]

no it works with the table, but it is not compatible with the ipairs loop i am using

[azqjanna]

What does this mean? Is there code u didn’t show that affects what people would recommend you do?

[concat_nate]

this is better, i just make it

local function ShiftHandler(t, i, callback)
    did_remove = callback(i)
    
    if i == #t then
       return
   elseif did_remove == true then
       ShiftHandler(t, i, callback)
   else
       ShiftHandler(t, i + 1, callback)
    end;
end;

local t = {1, 2, 3, 4, 4, 5, 6, 6, 7, 8, 4, 3, 5, 5};
local function sort(i)
    local v = t[i]
    
    if v < 5 then
        table.remove(t, i)
        return true
    end
    
    return false
end;

ShiftHandler(t, 1, sort)
print(t)

[azqjanna]

Better at what?
123123123123123123

[VanillaMokah]

something I can recommend is using a function that filters this table out. Something like this

local sample = {1,2,3,4,5,6}

local function check(value)
    if value < 5 then return false
    return true
end

local function filter(array, filterFunction)
    local newArray = {}

    for _, v in array do
        if not filterFunction(v) then continue end --Will insert into the new table IF its a truthy
        table.insert(newArray, v)
    end

    return newArray
end

filter(sample, check)

[azqjanna]

filter returns a new table but is called like it mutates sample