table.sort isn’t working right with strings that contain numbers.
Here is an example (don’t pay attention to the letters, just numbers).
list = {"8h","1a","2b","4d","5e","10j","6f","3c","7g","9i"}
What I’m expecting: {"1a","2b","3c",4d","5e","6f","7g","8h","9i","10j"}
What I get: {"1a",10j","2b","3c",4d","5e","6f","7g","8h","9i"} 10 is after 1 and before 2
It even happens in studio itself
(these models are sorted by the explorer, not by me)
This is because it’s sorting based on the first number. So even though 10 is higher than 9, it’s sorting it based on the 1 in the first digit.
I know but is this possible to make it sort like I want?
Im not exactly sure if you can, Studio automatically sorts stuff this way so i have no idea
You can probably do #list
I just check how many digits the highest number has, and then add zeros to all the smaller numbers until they also have the same number of digits, like:
Is there a method that can do that automatically? In Python it’s zfill
Not to my knowledge, I just use a loop, like this:
local list = {"1Value", "2Value", "3Value" ...}
local highest = nil
for i, v in ipairs(list) do
if tonumber(v) ~= nil and (highest == nil or tonumber(v) > highest) then
highest = tonumber(v)
end
end
for i, v in ipairs(list) do
if tonumber(v) ~= nil then
while string.len(tonumber(v) .. "") < string.len(highest .. "") do
v = "0" .. v
end
end
end
(I just wrote this from memory, if it doesn’t work tell me.)
Uhh I think it ran into an infinite loop…
Weird I’ll check it out, and come back to you.
I kind of figured out how to fix the sorting, but this function returns dictionary instead of table
EDIT: nevermind
function sort(tbl)
local indexes = {}
for i,str in pairs(tbl) do
local numChar = ""
local number = false
for _,char in pairs(str:split("")) do
if tonumber(char) then
number = true
numChar ..= char
else
if number then
break --this will sort strings only by their first numbers example a11bbb0 will only be sorted by 11
end
end
end
indexes[tonumber(numChar)] = str
end
local keys = {}
for k,v in pairs(indexes) do
table.insert(keys,k)
end
table.sort(keys, function(a,b)
return a < b
end)
local result = {}
for i,v in pairs(keys) do
table.insert(result,indexes[v])
end
return result
end
(it’s a bit chaotic tbh)
Wait no… it returns a table, I was just trying to get [0] from it. I can’t get used to it
I whole heartedly agree!
Anyways I saw you got an answer, but I will put my fixed code in case anyone wants it:
local function getNumberFromString(str)
if typeof(str) == "string" then
return string.gsub(str, "[^0-9]+[A-Za-z0-9]+", function(s) return "" end)
else
return nil
end
end
local list = {"1Value", "2Value", "30Value"}
local highest = nil
for i, v in ipairs(list) do
if getNumberFromString(v) ~= nil and (highest == nil or getNumberFromString(v) > highest) then
highest = getNumberFromString(v)
end
end
for i, v in ipairs(list) do
if getNumberFromString(v) ~= nil then
while string.len(getNumberFromString(v) .. "") < string.len(highest .. "") do
v = "0" .. v
end
--[[
local val = Instance.new("StringValue")
val.Name = v
val.Value = v
val.Parent = script
]]
end
end
For future reference, when using numbers to sort names, just put a 0 in front of the number if it’s single digit. 01, 02, 03, 04, 05, 06, 07, 08, 09, 10, 11, 12
Also this if the numbers will go up to more digits: 001, 002, 003, 004, 005, 006, 007, 008, 009, 010, 020, 050, 090, 100. Just add more zeros in front so that all numbers have same digits.
Yes, that’s why we made the above code snippets.