Hello! I have problems with split strings. I’m creating string hasher, and wanna split value “30203” with string “0” (so result will be like “3”,“2”,“3”) but i’m getting: “1”. only “1”, nothing more. Only one value, and it’s “1”. How to fix it?
P.S i using str.split(str, “0”)
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Are you sure?
what is the complete code?
Does the string actually contain a 0 in it?
local keys = string.split(key, "0")
for key in keys do
print(key.. " - key")
end
Output:
1 - key - Server
It contains “0” in it, you can check, i told you the string
Basically string.split removes characters based on whats been provided. The second argument is what is supposed to be removed. Then it finds all occurrences of that character and deletes it. The leftovers are made into a table
oops i accidentally replied to you
Gives 1 since that is the index of the table, to get the string you have to add another variable
local keys = string.split("323", "0")
for index, key in pairs(keys) do
print(key.. " - key")
end
and only print the first value because you don’t use pairs
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for key, value in pairs(keys) do
That’s the proper way to write a for loop
ur doing str.split(str,"0") I suppose “str” is 30203 so ur doing it wrong the first argument is already given it would be.
local str = "30203"
print(str.split("0")) -- 3,2,3
That’s not actually correct unless you use method syntax, and neither of you are. You need to change your code to method syntax if you want to omit str as the first argument:
str:split(“0”)
1 Like
Most string library functions automatically coerce number values/literals into string values/literals, the following is valid.
string.split(10203, 0) --Splits number into table containing 1, 2, 3.
Can you show us how you are using the split function