Hi there, I wanted to try using math.ceil for a game, but I have never used it before. The api info says that it returns the smallest number greater than or equal to X. Is there a way I can make it always be greater than? Because I can’t think of an instance where I would need to use it for equal to?
Not understanding what you’re asking for.
You want a function such that ceil(5) == 6
and ceil(5.1) == 6
instead of ceil(5) == 5
?
Default behavior of math.ceil
is that math.ceil(x)
will be x
if x
is an integer, and will be x - x % 1 + 1
if x`` has a fractional component. So: ceil(5) == 5
and ceil(5.1) == 6
Yes, because I had a value for a table, and it was zero, and when I did math.ceil it returned 0, and I don’t want that.
I’m thinking of two scenarios you might be having.
The first is you actually want to do this:
index = math.ceil(x + 1)
and the second is that you want to do this, given what you have said:
index = math.max(math.floor(x + 1), math.ceil(x))
Both are different scenarios.
I think you want the first one because I am assuming that you have an array with indexes being integers 1
to n
but n
is defined from all numbers between [0, n - 1]
.
Out of curiosity, why would you not want math.ceil(0)
to return 0?
Lua has 1-indexed arrays, which would require incrementing the number by 1. I’m not sure what his issue is though, but I’ve had reasons where I would want behavior as in the first codeblock I described.
I believe that you can index at 0, just that iterators like ipairs
and pairs
skip over it.
Lua arrays start at 1, not 0. If you define a 0 key it becomes a mixed table because it is now a dictionary.
local a = {}
table.insert(a, "hello")
print(a[0]) -- nil
print(a[1]) -- hello
a[0] = "world"
print(a[0]) -- "world"
print(a[1]) -- hello
What would be the point of the whole function then?
To ceil? math.ceil
is equivalent to rounding upwards. If your parameter is already an integer, rounding up is equivalent to rounding to the current value.
Ooooooooooooh I see I thought it would do it even if it was an integer. Thanks
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