Waiting for one of two events to fire

anon92559147 · August 16, 2019, 2:35pm

So right now im working on an animation system which freezes the player while the animation plays, however if the player switches tool while the animation is playing Track.Stopped does not fire , so how would I modify this code to make ‘1’ print when ither a. the animation finishes, b. the tool is unequipped

RamJoT · August 16, 2019, 2:54pm

I think you need to have a tool.equiped function to set a flag then use that flag inside this module.

haash_im · August 16, 2019, 2:55pm

I have always used a sort of hacky method to do this.

local condition = false

local conn, conn2

conn = Track.Stopped:Connect(function()
conn:Disconnect()
conn2:Disconnect()
condition = true
end)

conn = Tool.Unequipped:Connect(function()
conn:Disconnect()
conn2:Disconnect()
condition = true
end)

repeat wait() until condition

anon92559147 · August 16, 2019, 3:27pm

eh, I knew I could do this, I was just wondering if there was a simpler more memory efficient way

AbiZinho · August 16, 2019, 3:38pm

It’s quite easy with BindableEvents if used as the following:

Avoiding wait() and why

You can do something like:

local yield, con, con2 = Instance.new("BindableEvent")

con = Track.Stopped:Connect(function()
    yield:Fire()
end)

con2 = Tool.Unequipped:Connect(function()
    yield:Fire()
end)

yield.Event:Wait() -- Waits until either one of the events are fired
con:Disconnect()
con2:Disconnect()

-- Edited Code to fit the scenario :)