When I modify a table that is not frozen, it throws an error?

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#1

I modified ‘CopiedTable.Common’, yet I get an error which makes it look like I modified ‘shopWithRarities.Common’.
The error is ‘Attempt to modify a readonly table’
How can I avoid this?

local CopiedTable = {}
for i,v in pairs(shopWithRarities) do
	CopiedTable[i] = v
end
		
table.freeze(shopWithRarities.Common)
		
for i = 1,6 do
	local pseudoRandom = randomGeneration:NextInteger(0,1000)
	
	if pseudoRandom >= 450 then --55%
		if #CopiedTable.Common > 0 then
			local itemAdded = CopiedTable.Common[randomGeneration:NextInteger(1,#CopiedTable.Common)]
			table.insert(itemsForSale,
				itemAdded
			)
			table.remove(CopiedTable.Common,table.find(CopiedTable.Common,itemAdded)) --Attempt to modify a readonly table
#2

I think it might be because of this.

local a = {v = false}
local b = a

a.v = true

print(b.v) --Prints true
#3

Since I can’t find an “unfreeze” method I’m assuming if you call table.freeze again it’ll “unfreeze” making it writable to.

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image1083×201 30.3 KB

https://developer.roblox.com/en-us/api-reference/lua-docs/table

#4 
local a = {true} local b = {} for i,v in pairs(a) do b[i] = v end print(a==b)

this prints false, so it should not be referencing each other?

#5

invalid argument #1 to ‘freeze’ (table is already frozen)

#6

Why exactly do you need it to be read-only in the first place? I can’t understand a reason for this usage.

#7

its for debugging, im trying to only change CopiedTable.Common, not ShopWithRarities.Common

#8

You need to clone the whole Common table as well, otherwise Lua will use the reference to the frozen table.

1 Like
#9 
local a = {{v = false}}
b = a[1]

a[1].v = true

print(b.v) --prints true
#10

Oh thank youuuuuuuuuuuuuuuuuuu

#11 
local tables = {}
table.freeze(tables)
print(table.isfrozen(tables)) --true
table.freeze(tables) --Errors: 'table is already frozen'
print(table.isfrozen(tables))