Why # operator is executed AFTER ^ operator?

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#1

Let’s look at this simple code:

local Mas = {1, 2, 3, 4, 5}
print(#Mas^2) --will error
print((#Mas)^2) --won't error

Why this works like this though? Why power operator has higher priority than length one?

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#2

Damn. That um. That sucks. Thanks for the cursed knowledge.

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#3

It’s because of the precedence in Lua.

Its kind of complicated, but its something like this

the # returns a number, but the precedence expects a number,

so putting it in brackets groups the length operation first, then applies the power.

Basically, use brackets when you want to sort which operation goes first. Heres another example:

print(10 / (10*10)) -- returns 0.1

print((10*10) / 10) -- returns 10
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#4

Lua thinks it’s this
#(Mas^2)
Instead of
(#Mas)^2

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