Why won't this round to the nearest hundredth?

Help and Feedback Scripting Support
#1 
	--edits the time of the int values so that the bullets know the time.
	
	fullTime.Value = math.floor(((song.TimeLength*100)+0.5))/100
	currTime.Value = math.floor(((song.TimePosition*100)+0.5))/100

This script is supposed to get the time value of a song and floor it to the hundredth, but it’s not working? What would be the issue?

1 Like
#2

Ok, let’s say TimeLength is 50. So for the process, it would be:

  1. 50 * 100 --> 5000
  2. 5000 + 0.5 --> 5000.5
  3. math.floor(5000.5) --> 5000
  4. 5000/100 --> 50

So, uhhh, the output number is the same as the input number…???

#3

Here, let me give you an example. The number I would usually get for time is something like this “1.4543793”. I would like to just get the first two decimal numbers.

#4

What is the output you are getting? Is it just the same as the input?
Try splitting it up and see where the problem is.
such as
local temp = song.TimePosition
print temp
temp = temp * 100
print temp
temp = temp + .5
print temp
temp = math.floor(temp)
print temp
temp = temp / 100
print temp

So you can check each step of the process

#5

If you are trying to get just the two decimal numbers, can’t you just::

  1. Convert the number into a string
  2. Use string match to get the two decimals by using string patterns.
  3. Convert the result to a number

I could provide a short code of it if you want.

#6 
local song = script.Song
song.Loaded:Wait()  -- Wait for the song to finish loading

local length = song.TimeLength
local roundedLength = math.floor(length * 100 + 0.5) / 100

print("Rounded Length:", roundedLength)
#7

Here is one I found after a search.

module.RoundDec = function(value,precision,up)
	precision = precision or 0
	value = tonumber(value) or 0
	value = value * math.pow(10,precision)
	if up then
		value = math.ceil(value)
	else
		value = math.floor(value)
	end
	value = value / math.pow(10,precision)
	return tonumber(string.format("%."..precision.."f",value))
end
#8

I always get a whole number, not a number that is #.## form.

#9

Let me clarify, let’s say I have a number 3.67828. You only want to get the first 2 decimal numbers, which is .67, without rounding it up or down. Is this correct?

#10

If you have that number I would want 3.67.

If the number was 16.35327, I would want 16.35.

If it was 134.321443, I would want 134.32. I just want the first two decimals and the whole number.

This worked at some point . . . not sure what I did. Maybe it is because it’s an int value object. Do they take decimals?

#11

Integers do not accept decimals.

But anyways, use the script provided by @SelDraken with the precision as 2 and up as false.

#12

That is why! I was not using a number value (instead I was using an int value). Thanks for the help, my rounding program actually worked.

1 Like
#13

Also, look at math.round instead of having to recalculate math.floor or cath.ceil.
It does exactly what you want, and you only have to do this:

value = math.round(value * 100)/100
#14

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