Sorry for the late reply. Timezones are funny, so if you reply late it’s okay, i did too.
…But can this work in reverse? This sounds stupid, but i’m relatively new to this advanced math.
So can i calculate the other two like this? I’d imagine it’s more complicated than that.
Thank you for pointing this out to me.
Not quite, since cross product is a one way function and you can’t really get an “inverse” cross product, there’s a little bit more you need to do. In the case of angular velocity,
angular velocity is the cross product of the position vector and tangential velocity, divided by (the norm of the position vector) squared. This will look something like this:
where omega is angular velocity, r is the position vector, and v is the tangential velocity.
As for getting the position vector from angular velocity and tangential velocity, I am not sure if this is possible as I have never experimented with it nor tried it.