the human will feel that they have accomplished something
1 Like
he will feel also that he wasted his time to smt that can be done in a lot less time / can be automatically done
1 Like
function CheckEvenOrOdd(x: Number?)
local val = math.mod(x, 2)
if val == 1 then
ifUnEven
elseif val == 0 then
ifEven
end
Just use the modulus operator
function isEven(n)
local count = 0
-- We have to make sure this algorithm runs in O(n) time, since
-- O(n) is the best run time possible!
for i = 1, n do
count = count + 1
end
return not ((count / 2) % 1 == 1/2)
end
/s
Why are you even doing this by the way?
Even better:
function IsEven(Number)return Number%2==0;end
Yes, I made it in 1 line, and 45 characters total