How to get a letter of a string?

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#11

Isn’t string.match basically the same as string.find?

#12

I forgot to put the #1 in “” but it gave me nil even though I did the same thing.

#13

string.find finds positions, while string.match searches for a match in a string, returning the match. string.match is more intended for use with the string patterns (the Roblox equivalent of Regex)

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#14

nil means that what you are searching for was not found in the string

#15

Oh I though it was searching for the position

#16

It is searching for the position. If it can’t find what it is looking for, then there is no position and it returns nil

#17

I’m just gonna give the exact explanation of what I’m trying to do:

I have a DataStore string with “111111111111”
and I wanna change a specific letter/number in the string.
I’m trying to change the 2nd letter in the string so it would turn into 121111111111 keeping all the original values and just changing that “1” into a “2”.

#18

So you just want to change the nth character in a string, regardless of the contents of the string?

#19

Essentially, yes, keep all letters the same and just changing the 2nd letter without effecting the rest.

#20

In that case, you could do something like

local String = "11111111111111111111111" 

local n = 2 -- Position to replace
local ReplaceWith = "2" -- Replace the nth character with this

local Result = string.sub(String, 1, 1) .. ReplaceWith .. string.sub(String, n+1, -1)
#21 
local function swapChar(string, char, with)
    return string:sub(1, char - 1) .. with .. string:sub(char + 1)
end

print(swapChar("11111", 2, "2")) --> 12111
#22

I will go try this, I’ll mark it the solution if it works

#23

Just a quick question, will this work if n was 1?

#24

if n = 1 then it would replace the first character

“21111111111111111111111”

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#25

It doesn’t do that, it instead add 2 after the 1st character, also making the string 13 characters not 12

I meant to quote Bones not Seargent I don’t know why it did that

#26

well i see the issue with his code
edit: @avodey did it properly

local String = "111" 
local n = 1 -- Position to replace
local ReplaceWith = "2"

local Result = string.sub(String, 1, n - 1) .. ReplaceWith .. string.sub(String, n + 1, -1)
print(Result) --> 211

i think it would be easier to just specify which occurrence i want to replace instead of specifying position
if i had a string like this “123414914104412351351” and i want to replace the 3rd “1”, then i would need to figure out the position just so i could use a swapChar function.

#27

The reply he gave with a function should work

#28 
local function replace(word: string, pos: number, letter: char): string
    local t = string.split(word, "")
    t[pos] = letter
    return table.concat(t, "")
end

print(replace("111111111111", 1, "2")) -- 211111111111
#29

This is find first occurrence …

local str = "hello world"
local letter = "o"

local position = string.find(str, letter)

if position then
	print(letter .." is at position: ".. position)
end

There is a world of things you can do with a string. Maybe it would be better to just say what you are doing fully and not have us looking for a position…

#30

I have no idea why I didn’t try this yet, but it works!

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